Up to 50% Off + 10% Off! Code: SPOOK Ends: 10/31 Details
  1. Help

Chemistry lab report

Hello, you either have JavaScript turned off or an old version of Adobe's Flash Player. Get the latest Flash player.

Chemistry lab report - Page Text Content

FC: Chemistry Lab Report

1: Sunshine Christian Bilingual Institute 11th grade Mr. Jose Popoff Stoichiometric Relationships 11/2/12

2: Introduction | Carbon dioxide is a gas that does not causes danger and can be liberated easily from several carbon compounds, particularly from carbonates and bicarbonates like Pepsi or coca-cola. In this lab we will use baking soda in order to determine the mole ratio between a reactant and its product.

3: Objectives | Demonstrate the relationship between the moles of reactant and the moles of product in a chemical reaction.

4: Procedure | 1. The materials where prepared. 2. We cleaned the evaporating dish and rinsed it with distilled water. 3.Using the crucible tongs and holding the evaporating dish in a burner flame,we remove all the moisture. 4.We obtained some hydrogen carbonate on a piece of paper. 6. After the dish was ready, we measured its mass. 7. We added about 3.00g of NaHCO3 to the evaporating dish while it was still on the balance, we recorded the combined mass.

5: 8. We reacted the NaHCO3 with the HCL covering the evaporating dish with a small watch glass. 9. We obtained about 6ml of 6 M HCL in a test tube and gradually added the acid to the NaHCO3. 10. We removed the watch glass and rinsed the spattered material. 11. Finally we boiled off the water and determine the mass of the NaCl.

6: Results | 1. Mass of evaporating dish. -------------------54.4g 2. Mass of evaporating dish plus NaHCO3----57.1g 3. Mass evaporating dish +NaCl weighing 1---53.6g 4. Mass of evaporating dish +NaCl weighing 2--80.4g

7: Conclusion | *Carbon dioxide is a gas that does not causes danger and can be liberated easily from several carbon compounds. *The reaction is ideal for determining a mole ratio for several reactions. *The experimental mole ratio is equal to the theoretical mole ratio.

Sizes: mini|medium|large|massive
Default User
  • By: Nelson M.
  • Joined: over 4 years ago
  • Published Mixbooks: 4
No contributors

About This Mixbook

  • Title: Chemistry lab report
  • stoichoimetric relationships
  • Tags: None
  • Published: almost 4 years ago

Get up to 50% off
Your first order

Get up to 50% off
Your first order